Cell Relay Archive[Date Prev][Date Next][Thread Prev][Thread Next] [Date Index][Thread Index][Author Index][Subject Index] Re: CR: Self-Synchronous Scrambling (1 + x^43)
U can refer to the following book:
"Scrambling Techniques for Digital Transmission",
Byeong Gi Lee and Seok Chang Kim,
Springer-Verlag, ISBN 3-540-19863-6 / ISBN 0-387-19863-6
As far as the verilog equation goes, Please check the
following.
for scrambling in the transmit direction (bit serial),
in ------> 2-input ---------> Out
+-> XOR |
out_pre[43]| |
+--- 43 FFs <-----+
"in" is unscrambled cell and "out" is scrambled output.
assign out = tx_payload_xsfer_on ?
(in ^ out_pre [43]) : in ;
always @(posedge clk)
begin
if (tx_payload_xsfer_on)
out_pre [43:1] <= {out_pre [42:1], out} ;
else
out_pre <= out_pre ; // dont feed out into scr
end
tx_payload_xsfer_on is active when payload bits are being sent
and inactive during header bits coming over "in".
For the descrambler, it is
in ----------------------> 2-input -----> Out
| +--> XOR
| |
+--- 43 FFs ---+
"in" is scrambled cell coming serially and out is the
descrambled output.
(Note that this is a feed-forward circuit unlike the
feedback circuit in the transmit side)
assign out = rx_payload_xsfer_on ?
(in ^ in_ff [43]) : in ;
always @(posedge clk)
begin
if (rx_payload_xsfer_on)
in_ff [43:1] <= {in_ff [42:1], in} ;
else
in_ff <= in_ff ; // dont feed into descr
end
Mathematically,
the scrambled output is Y(K) = X(K) ^ Y(K-43)
the descrambled output is Y(K) ^ Y(K-43)
= X(K) ^ Y(K-43) ^ Y(K-43)
= X(K)
The descrambler is a feed-forward circuit and the scrambler
being feedback one. All it needs for descrambler to
synchronize is just 43 bits of error-free payload bits.
Hope it helps,
Raj
Funda Kutay wrote:
> Hello,
>
> I am looking for information about how
> 1 + x^43 scrambling/descrambling is done.
> I myself made a verilog code to understand it.
> But it seems I am missing some points.
>
> Thank you for the help.
>
> Funda
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